Kaydet (Commit) 2a65ecb7 authored tarafından Berker Peksag's avatar Berker Peksag

Issue #26130: Remove redundant variable 's' from Parser/parser.c

Patch by Oren Milman.
üst 5a6c018b
...@@ -140,21 +140,20 @@ classify(parser_state *ps, int type, const char *str) ...@@ -140,21 +140,20 @@ classify(parser_state *ps, int type, const char *str)
int n = g->g_ll.ll_nlabels; int n = g->g_ll.ll_nlabels;
if (type == NAME) { if (type == NAME) {
const char *s = str;
label *l = g->g_ll.ll_label; label *l = g->g_ll.ll_label;
int i; int i;
for (i = n; i > 0; i--, l++) { for (i = n; i > 0; i--, l++) {
if (l->lb_type != NAME || l->lb_str == NULL || if (l->lb_type != NAME || l->lb_str == NULL ||
l->lb_str[0] != s[0] || l->lb_str[0] != str[0] ||
strcmp(l->lb_str, s) != 0) strcmp(l->lb_str, str) != 0)
continue; continue;
#ifdef PY_PARSER_REQUIRES_FUTURE_KEYWORD #ifdef PY_PARSER_REQUIRES_FUTURE_KEYWORD
#if 0 #if 0
/* Leaving this in as an example */ /* Leaving this in as an example */
if (!(ps->p_flags & CO_FUTURE_WITH_STATEMENT)) { if (!(ps->p_flags & CO_FUTURE_WITH_STATEMENT)) {
if (s[0] == 'w' && strcmp(s, "with") == 0) if (str[0] == 'w' && strcmp(str, "with") == 0)
break; /* not a keyword yet */ break; /* not a keyword yet */
else if (s[0] == 'a' && strcmp(s, "as") == 0) else if (str[0] == 'a' && strcmp(str, "as") == 0)
break; /* not a keyword yet */ break; /* not a keyword yet */
} }
#endif #endif
......
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