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Tim Peters yazdı
ah*bh and al*bl. This is much easier than explaining why that's true for (ah+al)*(bh+bl), and follows directly from the simple part of the (ah+al)*(bh+bl) explanation.
8e966ee4
ah*bh and al*bl. This is much easier than explaining why that's true for (ah+al)*(bh+bl), and follows directly from the simple part of the (ah+al)*(bh+bl) explanation.