Unverified Kaydet (Commit) 2b7f93b9 authored tarafından Stéphane Wirtel's avatar Stéphane Wirtel Kaydeden (comit) GitHub

bpo-36345: Update wsgiref example (GH-12562)

Use literalinclude markup to include Tools/scripts/serve.py code.
Tools/scripts/serve.py first argument on the command line is now optional.
üst 6fa84bd1
......@@ -783,33 +783,7 @@ This is a working "Hello World" WSGI application::
httpd.serve_forever()
Example of a small wsgiref-based web server::
# Takes a path to serve from and an optional port number (defaults to 8000),
# then tries to serve files. Mime types are guessed from the file names, 404
# errors are raised if the file is not found.
import sys
import os
import mimetypes
from wsgiref import simple_server, util
def app(environ, respond):
fn = os.path.join(path, environ['PATH_INFO'][1:])
if '.' not in fn.split(os.path.sep)[-1]:
fn = os.path.join(fn, 'index.html')
type = mimetypes.guess_type(fn)[0]
if os.path.exists(fn):
respond('200 OK', [('Content-Type', type)])
return util.FileWrapper(open(fn, "rb"))
else:
respond('404 Not Found', [('Content-Type', 'text/plain')])
return [b'not found']
path = sys.argv[1]
port = int(sys.argv[2]) if len(sys.argv) > 2 else 8000
with simple_server.make_server('', port, app) as httpd:
print("Serving {} on port {}, control-C to stop".format(path, port))
# Serve until process is killed
httpd.serve_forever()
Example of a WSGI application serving the current directory, accept optional
directory and port number (default: 8000) on the command line:
.. literalinclude:: ../../Tools/scripts/serve.py
Avoid the duplication of code from ``Tools/scripts/serve.py`` in using the
:rst:dir:`literalinclude` directive for the basic wsgiref-based web server in the
documentation of :mod:`wsgiref`. Contributed by Stéphane Wirtel.
......@@ -25,11 +25,12 @@ def app(environ, respond):
return [b'not found']
if __name__ == '__main__':
path = sys.argv[1]
path = sys.argv[1] if len(sys.argv) > 1 else os.getcwd()
port = int(sys.argv[2]) if len(sys.argv) > 2 else 8000
httpd = simple_server.make_server('', port, app)
print("Serving {} on port {}, control-C to stop".format(path, port))
try:
httpd.serve_forever()
except KeyboardInterrupt:
print("\b\bShutting down.")
print("Shutting down.")
httpd.server_close()
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