Kaydet (Commit) d6844155 authored tarafından Tim Peters's avatar Tim Peters

I give up: unless I write my own strftime by hand, datetime just can't

be trusted with years before 1900, so now we raise ValueError if a date or
datetime or datetimetz .strftime() method is called with a year before
1900.
üst 83b85f1d
......@@ -868,6 +868,12 @@ class TestDate(unittest.TestCase):
self.failUnless(self.theclass.min)
self.failUnless(self.theclass.max)
def test_srftime_out_of_range(self):
# For nasty technical reasons, we can't handle years before 1900.
cls = self.theclass
self.assertEqual(cls(1900, 1, 1).strftime("%Y"), "1900")
for y in 1, 49, 51, 99, 100, 1000, 1899:
self.assertRaises(ValueError, cls(y, 1, 1).strftime, "%Y")
#############################################################################
# datetime tests
......
......@@ -940,6 +940,31 @@ wrap_strftime(PyObject *object, PyObject *format, PyObject *timetuple)
assert(object && format && timetuple);
assert(PyString_Check(format));
/* Give up if the year is before 1900.
* Python strftime() plays games with the year, and different
* games depending on whether envar PYTHON2K is set. This makes
* years before 1900 a nightmare, even if the platform strftime
* supports them (and not all do).
* We could get a lot farther here by avoiding Python's strftime
* wrapper and calling the C strftime() directly, but that isn't
* an option in the Python implementation of this module.
*/
{
long year;
PyObject *pyyear = PySequence_GetItem(timetuple, 0);
if (pyyear == NULL) return NULL;
assert(PyInt_Check(pyyear));
year = PyInt_AsLong(pyyear);
Py_DECREF(pyyear);
if (year < 1900) {
PyErr_Format(PyExc_ValueError, "year=%ld is before "
"1900; the datetime strftime() "
"methods require year >= 1900",
year);
return NULL;
}
}
/* Scan the input format, looking for %z and %Z escapes, building
* a new format. Since computing the replacements for those codes
* is expensive, don't unless they're actually used.
......
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