Kaydet (Commit) dab08963 authored tarafından Mark Dickinson's avatar Mark Dickinson

Merged revisions 82607 via svnmerge from

svn+ssh://pythondev@svn.python.org/python/branches/py3k

........
  r82607 | mark.dickinson | 2010-07-06 16:00:40 +0100 (Tue, 06 Jul 2010) | 1 line

  Indentation and PEP 7 fixes.
........
üst c167712c
......@@ -55,7 +55,8 @@ _Py_acosh(double x)
else if (x >= two_pow_p28) { /* x > 2**28 */
if (Py_IS_INFINITY(x)) {
return x+x;
} else {
}
else {
return log(x)+ln2; /* acosh(huge)=log(2x) */
}
}
......@@ -173,15 +174,15 @@ _Py_expm1(double x)
*/
if (fabs(x) < 0.7) {
double u;
u = exp(x);
if (u == 1.0)
return x;
else
return (u - 1.0) * x / log(u);
double u;
u = exp(x);
if (u == 1.0)
return x;
else
return (u - 1.0) * x / log(u);
}
else
return exp(x) - 1.0;
return exp(x) - 1.0;
}
/* log1p(x) = log(1+x). The log1p function is designed to avoid the
......@@ -213,17 +214,19 @@ _Py_log1p(double x)
double y;
if (fabs(x) < DBL_EPSILON/2.) {
return x;
} else if (-0.5 <= x && x <= 1.) {
/* WARNING: it's possible than an overeager compiler
will incorrectly optimize the following two lines
to the equivalent of "return log(1.+x)". If this
happens, then results from log1p will be inaccurate
for small x. */
y = 1.+x;
return log(y)-((y-1.)-x)/y;
} else {
/* NaNs and infinities should end up here */
return log(1.+x);
return x;
}
else if (-0.5 <= x && x <= 1.) {
/* WARNING: it's possible than an overeager compiler
will incorrectly optimize the following two lines
to the equivalent of "return log(1.+x)". If this
happens, then results from log1p will be inaccurate
for small x. */
y = 1.+x;
return log(y)-((y-1.)-x)/y;
}
else {
/* NaNs and infinities should end up here */
return log(1.+x);
}
}
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