Simplify ranges overlapping condition

Using conjuction and disjuction distributivity and assuming
that for each range r: r.mnStart <= r.mnEnd.

Change-Id: Ifbd156426617ebf225b1b1139e17e4967a228cd6
Reviewed-on: https://gerrit.libreoffice.org/68003
Tested-by: Jenkins
Reviewed-by: Noel Grandin <noel.grandin@collabora.co.uk>

editeng/source/editeng/edtspell.cxx

@@ -508,12 +508,7 @@ bool WrongList::DbgIsBuggy() const
     {
         for (WrongList::const_iterator j = i + 1; !bError && (j != maRanges.end()); ++j)
         {
-            // 1) Start before, End after the second Start
-            if (i->mnStart <= j->mnStart && i->mnEnd >= j->mnStart)
-                bError = true;
-            // 2) Start after the second Start, but still before the second End
-            else if (i->mnStart >= j->mnStart && i->mnStart <= j->mnEnd)
-                bError = true;
+            bError = i->mnStart <= j->mnEnd && j->mnStart <= i->mnEnd;
         }
     }
     return bError;