lok: Expose DisplayName of styles, not internal ones

Change-Id: I2119713600703e3aa18f673979c7cd84c38177d7
Reviewed-on: https://gerrit.libreoffice.org/22349Tested-by: Jenkins <ci@libreoffice.org>
Reviewed-by: Andras Timar <andras.timar@collabora.com>

desktop/source/lib/init.cxx

@@ -1375,9 +1375,28 @@ static char* getStyles(LibreOfficeKitDocument* pThis, const char* pCommand)
         uno::Sequence<OUString> aStyles = xStyleFamily->getElementNames();
         for (const OUString& rStyle: aStyles )
         {
-            // Filter out the default styles - they are already at the top
-            // of the list
-            if (aDefaultStyleNames.find(rStyle) == aDefaultStyleNames.end())
+            uno::Reference< beans::XPropertySet > xStyle (xStyleFamily->getByName(rStyle), uno::UNO_QUERY);
+            bool bStyleInserted = false;
+            // Its possible that the style does not implement XPropertySet.
+            // For example, TableDesignFamily doesn't yet.
+            if (xStyle.is())
+            {
+                // Filter out the default styles - they are already at the top
+                // of the list
+                OUString sName;
+                xStyle->getPropertyValue("DisplayName") >>= sName;
+                if (!sName.isEmpty() && aDefaultStyleNames.find(sName) == aDefaultStyleNames.end())
+                {
+                    boost::property_tree::ptree aChild;
+                    aChild.put("", sName.toUtf8());
+                    aChildren.push_back(std::make_pair("", aChild));
+                    bStyleInserted = true;
+                }
+            }
+
+            // If XPropertySet is not implemented or DisplayName is empty string,
+            // fallback to LO internal names
+            if (!bStyleInserted)
             {
                 boost::property_tree::ptree aChild;
                 aChild.put("", rStyle);