Assume m_vEntries.size() == 2; assume first element (nPos == 0) is m_bActive,
gets removed, so m_nActive would have stayed at 0 and m_bHasActive at true; then
assume second element (again nPos == 0, due to the removed element) is m_bNew,
so nPos <= m_nActive is true and m_nActive gets updated to 1 (and m_bHasActive
remains true); then selectEntry(nNewPos) (nNewPos == 0) would have tried to
reset m_vEntries[1]->m_bActive but now m_vEntries.size() == 1.

Change-Id: I31d3bbe97ca99f880aa99bdea015f7c0457f8331